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In how many ways can a team of 3 boys and 3 girls be selected from 5 boys and 4 girls?

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Question

In how many ways can a team of 3 boys and 3 girls be selected from 5 boys and 4 girls?

Sum
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Solution

A team of 3 boys and 3 girls is to be selected from 5 boys and 4 girls.

3 boys can be selected from 5 boys in `""^5C_3` ways.

3 girls can be selected from 4 girls in `""^4C_3 `ways.

Therefore, by multiplication principle, number of ways in which a team of 3 boys  and 3 girls can be selected

= 5C3 x 4C3

= `(5!)/(3!2!) xx (4!)/(3!1!)`

= `(5 xx 4 xx 3!)/(3! xx 2) xx (4 xx 3!)/(3!)` 

= 10 x 4 = 40

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Chapter 6: Permutations and Combinations - EXERCISE 6.4 [Page 119]

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NCERT Mathematics [English] Class 11
Chapter 6 Permutations and Combinations
EXERCISE 6.4 | Q 4. | Page 119

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