English

In a small village, there are 87 families, of which 52 families have atmost 2 children. In a rural development programme 20 families are to be chosen for assistance, of which atleast 18 families must

Advertisements
Advertisements

Question

In a small village, there are 87 families, of which 52 families have atmost 2 children. In a rural development programme 20 families are to be chosen for assistance, of which atleast 18 families must have at most 2 children. In how many ways can the choice be made?

Sum
Advertisements

Solution

It is given that out of 87 families

52 families have at most 2 children

So other 35 families are of other type.

For rural development programme

20 families are to be chosen for assistance, of which at least 18 families must have atmost 2 children.

Thus, the following are the number of possible choices:

52C18 × 35C2 (18 families having atmost 2 children and 2 selected from other type of families)

52C19 × 35C2 (19 families having at most 2 children and 1 selected from other type of families)

52C20 (All selected 20 families having atmost 2 children)

Hence, the total number of possible choices is

52C18 × 35C2 + 52C19 × 35C2 + 35C1 + 52C20 

shaalaa.com
  Is there an error in this question or solution?
Chapter 7: Permutations and Combinations - Solved Examples [Page 119]

APPEARS IN

NCERT Exemplar Mathematics [English] Class 11
Chapter 7 Permutations and Combinations
Solved Examples | Q 10 | Page 119

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Determine n if  `""^(2n)C_3 : ""^nC_3 = 12 : 1`


Determine the number of 5 card combinations out of a deck of 52 cards if there is exactly one ace in each combination.


Compute:

\[\frac{11! - 10!}{9!}\]

Prove that

\[\frac{1}{9!} + \frac{1}{10!} + \frac{1}{11!} = \frac{122}{11!}\]

A mint prepares metallic calendars specifying months, dates and days in the form of monthly sheets (one plate for each month). How many types of calendars should it prepare to serve for all the possibilities in future years?


There are four parcels and five post-offices. In how many different ways can the parcels be sent by registered post?


In how many ways can an examinee answer a set of ten true/false type questions?


How many A.P.'s with 10 terms are there whose first term is in the set {1, 2, 3} and whose common difference is in the set {1, 2, 3, 4, 5}?


Evaluate the following:

35C35


Evaluate the following:

n + 1Cn


24Cx = 24C2x + 3, find x.


If 2nC3 : nC2 = 44 : 3, find n.


How many different products can be obtained by multiplying two or more of the numbers 3, 5, 7, 11 (without repetition)?


There are 10 points in a plane of which 4 are collinear. How many different straight lines can be drawn by joining these points.


A parallelogram is cut by two sets of m lines parallel to its sides. Find the number of parallelograms thus formed.


Find the number of ways in which : (a) a selection


If 20Cr = 20Cr−10, then 18Cr is equal to


If nCr + nCr + 1 = n + 1Cx , then x =


If\[\ ^{( a^2 - a)}{}{C}_2 = \ ^{( a^2 - a)}{}{C}_4\] , then a =


If C0 + C1 + C2 + ... + Cn = 256, then 2nC2 is equal to


The number of diagonals that can be drawn by joining the vertices of an octagon is


If n + 1C3 = 2 · nC2 , then n =


Find n and r if `""^"n""P"_"r"` = 720 and `""^"n""C"_("n" - "r")` = 120


Find the number of ways of drawing 9 balls from a bag that has 6 red balls, 5 green balls, and 7 blue balls so that 3 balls of every colour are drawn.


A student finds 7 books of his interest, but can borrow only three books. He wants to borrow Chemistry part II book only if Chemistry Part I can also be borrowed. Find the number of ways he can choose three books that he wants to borrow.


Four parallel lines intersect another set of five parallel lines. Find the number of distinct parallelograms that can be formed.


Answer the following:

A question paper has 6 questions. How many ways does a student have to answer if he wants to solve at least one question?


A student has to answer 10 questions, choosing atleast 4 from each of Parts A and B. If there are 6 questions in Part A and 7 in Part B, in how many ways can the student choose 10 questions?


How many committee of five persons with a chairperson can be selected from 12 persons.


In how many ways can a football team of 11 players be selected from 16 players? How many of them will include 2 particular players?


A group consists of 4 girls and 7 boys. In how many ways can a team of 5 members be selected if the team has at least three girls.


Everybody in a room shakes hands with everybody else. The total number of handshakes is 66. The total number of persons in the room is ______.


The number of triangles that are formed by choosing the vertices from a set of 12 points, seven of which lie on the same line is ______.


The number of ways in which a team of eleven players can be selected from 22 players always including 2 of them and excluding 4 of them is ______.


Three balls are drawn from a bag containing 5 red, 4 white and 3 black balls. The number of ways in which this can be done if at least 2 are red is ______.


A scientific committee is to be formed from 6 Indians and 8 foreigners, which includes at least 2 Indians and double the number of foreigners as Indians. Then the number of ways, the committee can be formed is ______.


All possible numbers are formed using the digits 1, 1, 2, 2, 2, 2, 3, 4, 4 taken all at a time. The number of such numbers in which the odd digits occupy even places is ______.


There are 12 balls numbered from 1 to 12. The number of ways in which they can be used to fill 8 places in a row so that the balls are with numbers in ascending or descending order is equal to ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×