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Everybody in a room shakes hands with everybody else. The total number of handshakes is 66. The total number of persons in the room is ______.

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Question

Everybody in a room shakes hands with everybody else. The total number of handshakes is 66. The total number of persons in the room is ______.

Options

  • 11

  • 12

  • 13

  • 14

MCQ
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Solution

Everybody in a room shakes hands with everybody else. The total number of handshakes is 66. The total number of persons in the room is 12.

Explanation:

Let the total number of persons in a room be n since, two persons make 1 handshake

∴ The number of handshakes = nC2

So nC2 = 66

⇒ `(n!)/(2!(n - 2)!)` = 66

⇒ `(n(n - 1)(n - 2)!)/(2 xx 1 xx (n - 2)1)` = 66

⇒ `(n(n - 1))/2` = 66

⇒ n2 – n = 132

⇒ n2 – n – 132 = 0

⇒ n2 – 12n + 11n – 132 = 0

⇒ n(n – 12) + 11(n – 12) = 0

⇒ (n – 12)(n + 11) = 0

⇒ n – 12 = 0, n + 11 = 0

⇒ n = 12, n = – 11

∴ n = 12   ....(∵ n ≠ – 11)

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Chapter 7: Permutations and Combinations - Exercise [Page 125]

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NCERT Exemplar Mathematics [English] Class 11
Chapter 7 Permutations and Combinations
Exercise | Q 32 | Page 125

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