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Question
Determine n if `""^(2n)C_3 : ""^nC_3 = 11: 1`
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Solution
`(""^(2n)C_3)/(""^nC_3) = 11/1`
⇒ `((2n)!)/(3!(2n - 3)!) xx (3!(n - 3)!)/(n!) = 11/1`
⇒ `((2n)(2n - 1)(2n - 2)(2n - 3)!)/((2n - 3)!) xx ((n - 3)!)/(n(n - 1)(n - 2)(n - 3)!) = 11`
⇒ `(2(2n - 1)(2n - 2))/((n - 1)(n - 2)) = 11`
⇒ `(4(2n - 1)(n - 1))/((n - 1)(n - 2)) = 11`
⇒ `(4(2n - 1))/((n - 2)) = 11`
⇒ 4(2n - 1) = 11(n - 2)
⇒ 8n - 4 = 11n - 22
⇒ 11n - 8n = -4 + 22
⇒ 3n = 18
⇒ n = 6
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