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A committee of 6 is to be chosen from 10 men and 7 women so as to contain atleast 3 men and 2 women. In how many different ways can this be done if two particular women refuse to serve on the same

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A committee of 6 is to be chosen from 10 men and 7 women so as to contain atleast 3 men and 2 women. In how many different ways can this be done if two particular women refuse to serve on the same committee ______.

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Solution

A committee of 6 is to be chosen from 10 men and 7 women so as to contain atleast 3 men and 2 women. In how many different ways can this be done if two particular women refuse to serve on the same committee 7800.

Explanation:

We have 10 men and 7 women out of which a committee of 6 is to be formed which contain atleast 3 men and 2 women

Therefore, Number of ways = 10C3 × 7C3 + 10C4 × 7C2

= `(10 xx 9 xx 8)/(3 xx 2 xx 1) xx (7 xx 6 xx 5)/(3 xx 2 xx 1) + (10 xx 9 xx 8 xx 7)/(4 xx 3 xx 2 xx ) xx (7 xx 6)/(2 xx 1)`

= 120 × 35 + 210 × 21

= 4200 + 4410

= 8610

If 2 particular women to be always present, then the number of ways = 10C4 × 5C0 + 10C3 × 5C1

= `(10 xx 9 xx 8 xx 7)/(4 xx 3 xx 2 xx 1) xx 1 + (10 xx 9 xx 8)/(3 xx 2 xx 1) xx 5`

= 210 + 120 × 5

= 210 + 600

= 810

∴ Total number of committee = 8610 – 810 = 7800

Hence, the value of the filler is 7800.

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Chapter 7: Permutations and Combinations - Exercise [Page 126]

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NCERT Exemplar Mathematics Exemplar [English] Class 11
Chapter 7 Permutations and Combinations
Exercise | Q 49 | Page 126

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