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In an Examination, a Question Paper Consists of 12 Questions Divided into Two Parts I.E., Part I and Part Ii, Containing 5 and 7 Questions, Respectively - Mathematics

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Question

In an examination, a question paper consists of 12 questions divided into two parts i.e., Part I and Part II, containing 5 and 7 questions, respectively. A student is required to attempt 8 questions in all, selecting at least 3 from each part. In how many ways can a student select the questions?

Sum
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Solution

It is given that the question paper consists of 12 questions divided into two parts – Part I and Part II, containing 5 and 7 questions, respectively.

A student has to attempt 8 questions, selecting at least 3 from each part.

This can be done as follows.

  1. 3 questions from part I and 5 questions from part II
  2. 4 questions from part I and 4 questions from part II
  3. 5 questions from part I and 3 questions from part II

3 questions from part I and 5 questions from part II can be selected in `""^5C_3 xx ""^7C_5`ways.

4 questions from part I and 4 questions from part II can be selected in `""^5C_4 xx ""^7C_4` ways.

5 questions from part I and 3 questions from part II can be selected in `""^5C_5 xx  ""^7C_3` ways.

Thus, required number of ways of selecting questions

= 5C3 x 7C5 + 5C4 x 7C4 + 5C5 x 7C3

= `(5!)/(2!3!) xx (7!)/(2!5!) xx (5!)/(4!1!) xx (7!)/(4!3!) xx (5!)/(5!0!) xx (7!)/(3!4!)` 

= `(5 xx 4)/(2) xx (7 xx 6)/(2) + 5 xx (7 xx 6 xx 5)/(3 xx 2) + 1 xx (7xx 6 xx 5)/(3 xx 2)`

= 210 + 175 + 35

= 420

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Chapter 7: Permutations and Combinations - Miscellaneous Exercise [Page 157]

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NCERT Mathematics [English] Class 11
Chapter 7 Permutations and Combinations
Miscellaneous Exercise | Q 7 | Page 157

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