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The English alphabet has 5 vowels and 21 consonants. How many words with two different vowels and 2 different consonants can be formed from the alphabet? - Mathematics

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Question

The English alphabet has 5 vowels and 21 consonants. How many words with two different vowels and 2 different consonants can be formed from the alphabet?

Sum
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Solution

2 different vowels and 2 different consonants are to be selected from the English alphabet.

Since there are 5 vowels in the English alphabet, number of ways of selecting 2 different vowels from the alphabet

= `""^5C_2  =  (5!)/(2!3!)  = 10`

Since there are 21 consonants in the English alphabet, number of ways of selecting 2 different consonants from the alphabet 

= `""^21C_2  = (21!)/(2!19!)  = 210`

Therefore, number of combinations of 2 different vowels and 2 different consonants = 10 × 210 = 2100

Each of these 2100 combinations has 4 letters, which can be arranged among themselves in 4! ways.

Therefore, required number of words = 2100 × 4!

= 24 x 2100

= 50400

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Chapter 7: Permutations and Combinations - Miscellaneous Exercise [Page 157]

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NCERT Mathematics [English] Class 11
Chapter 7 Permutations and Combinations
Miscellaneous Exercise | Q 6 | Page 157

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