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Question
A regular polygon has 20 sides. The number of triangles that can be drawn by using the vertices but not using the sides is
Options
1140
800
340
20
MCQ
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Solution
800
Explanation:
Total triangles = \[^{20}\mathbb{C}_3\]
Triangles which have two sides common with polygon = 20
Triangle which have one side common with the polygon = \[20\times{}^{16}\mathrm{C}_{1}\]
∴ Required number of triangles
\[={}^{20}\mathrm{C}_3-20-20\times{}^{16}\mathrm{C}_1\]
\[=\frac{20\times19\times18}{1\times2\times3}-20-16\times20\]
= 20 (57 − 1 − 16)
= 20 × 40
= 800
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