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Find n and r if nPrnPr = 720 and nCnrnCn-r = 120

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Question

Find n and r if `""^"n""P"_"r"` = 720 and `""^"n""C"_("n" - "r")` = 120

Sum
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Solution

`""^"n""P"_"r"` = 720

∴ `("n"!)/(("n" - "r")!)` = 720  ...(i)

Also, `""^"n""C"_("n" - "r")` = 120

∴ `("n"!)/(("n" - "r")!("n"-"n"+"r")!) = 120`

∴ `("n"!)/("r"!("n" - "r")!)` = 120  ...(ii)

Dividing (i) by (ii), we get

∴ `(("n"!)/(("n"-"r")!))/(("n"!)/("r"!("n"-"r")!))=720/120`

∴ r!  = 6

∴ r = 3

Substituting r = 3 in (i), we get

∴ `("n"!)/(("n" - 3)!)` = 720

∴ `("n"("n" - 1)("n" - 2)("n" - 3)!)/(("n" - 3)!)` = 720

∴ n(n – 1)(n – 2) = 10 × 9 × 8

∴ n = 10

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Chapter 6: Permutations and Combinations - Exercise 6.6 [Page 89]

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Balbharati Mathematics and Statistics (Commerce) Part 2 [English] Standard 11 Maharashtra State Board
Chapter 6 Permutations and Combinations
Exercise 6.6 | Q 4. (i) | Page 89

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