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Find the number of ways of drawing 9 balls from a bag that has 6 red balls, 5 green balls, and 7 blue balls so that 3 balls of every colour are drawn.

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Question

Find the number of ways of drawing 9 balls from a bag that has 6 red balls, 5 green balls, and 7 blue balls so that 3 balls of every colour are drawn.

Sum
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Solution

Total number of balls = 6 + 5 + 7 = 18
Number of red balls = 6
Number of green balls = 5
Number of blue balls = 7
9 balls are to be drawn, 3 of each Colour,
No. of ways of drawing 3 red balls out of 6 red balls = 6C3
Similarly, No. of ways of drawing 3 green balls out of
5 green balls = 5C3
No. of ways of drawing 3 blue balls out of
7 blue balls = 7C3
∴ Total number of ways = 6C3 × 5C3 × 7C3 

= `(6!)/(3!3!) xx (5!)/(3!2!) xx (7!)/(3!4!)`

=`(6xx5xx4xx3!)/(3xx2xx1xx3!)xx(5xx4xx3!)/(3!xx2)xx(7xx6xx5xx4!)/(3xx2xx1xx4!)`

= 20 × 10 × 35

= 7000

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Chapter 6: Permutations and Combinations - Exercise 6.6 [Page 89]

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Balbharati Mathematics and Statistics 2 (Commerce) [English] 11 Standard Maharashtra State Board
Chapter 6 Permutations and Combinations
Exercise 6.6 | Q 7 | Page 89

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