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In the Expansion of ( 1 2 X 1 / 3 + X − 1 / 5 ) 8 , the Term Independent of X is (A) T5 (B) T6 (C) T7 (D) T8

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Question

In the expansion of \[\left( \frac{1}{2} x^{1/3} + x^{- 1/5} \right)^8\] , the term independent of x is

 

Options

  • T5

  •  T6

  •  T7

  • T8

     
MCQ
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Solution

T6
Suppose the (r + 1)th term in the given expansion is independent of x.
Thus, we have:

\[T_{r + 1} =^{8}{}{C}_r \left( \frac{1}{2} x^{1/3} \right)^{8 - r} ( x^{- 1/5} )^r \]

\[ = ^{8}{}{C}_r \frac{1}{2^{8 - r}} x^\frac{8 - r}{3} - \frac{r}{5} \]

\[\text{ For this term to be independent of x, we must have } \]

\[\frac{8 - r}{3} - \frac{r}{5} = 0\]

\[ \Rightarrow 40 - 5r - 3r = 0\]

\[ \Rightarrow r = 5\]

\[\text{ Hence, the required term is the 6th term, i . e  } . T_6\]

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Chapter 18: Binomial Theorem - Exercise 18.4 [Page 47]

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R.D. Sharma Mathematics [English] Class 11
Chapter 18 Binomial Theorem
Exercise 18.4 | Q 14 | Page 47

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