English

Find the middle term (terms) in the expansion of (px+xp)9.

Advertisements
Advertisements

Question

Find the middle term (terms) in the expansion of `(p/x + x/p)^9`.

Sum
Advertisements

Solution

Since the power of binomial is odd.

Therefore, we have two middle terms which are 5th and 6th terms.

These are given by

T5 = `""^9"C"_4 (p/x)^5 (x/p)^4`

= `""^9"C"_4 p/x`

= `(126p)/x`

And T6 = `""^9"C"_5 (p/x)^4 (x/p)^5`

= `""^9"C"_5 x/p`

= `(126x)/p`

shaalaa.com
  Is there an error in this question or solution?
Chapter 8: Binomial Theorem - Solved Examples [Page 135]

APPEARS IN

NCERT Exemplar Mathematics Exemplar [English] Class 11
Chapter 8 Binomial Theorem
Solved Examples | Q 9 | Page 135

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Find the coefficient of x5 in (x + 3)8


Find the coefficient of a5b7 in (a – 2b)12


Find the 4th term in the expansion of (x – 2y)12 .


The coefficients of the (r – 1)thrth and (r + 1)th terms in the expansion of (x + 1)n are in the ratio 1:3:5. Find n and r.


Prove that the coefficient of xn in the expansion of (1 + x)2n is twice the coefficient of xn in the expansion of (1 + x)2n–1 .


Find the middle terms in the expansion of:

(iv)  \[\left( x^4 - \frac{1}{x^3} \right)^{11}\]

 


Find the middle terms(s) in the expansion of: 

(i) \[\left( x - \frac{1}{x} \right)^{10}\]

 


Find the middle terms(s) in the expansion of:

(v) \[\left( x - \frac{1}{x} \right)^{2n + 1}\]

 


Find the middle terms(s) in the expansion of:

(ix)  \[\left( \frac{p}{x} + \frac{x}{p} \right)^9\]

 


Find the middle terms(s) in the expansion of:

(x)  \[\left( \frac{x}{a} - \frac{a}{x} \right)^{10}\]

 


Find the term independent of x in the expansion of the expression: 

(i) \[\left( \frac{3}{2} x^2 - \frac{1}{3x} \right)^9\]

 


Find the term independent of x in the expansion of the expression: 

(vii)  \[\left( \frac{1}{2} x^{1/3} + x^{- 1/5} \right)^8\]

 


Prove that the coefficient of (r + 1)th term in the expansion of (1 + x)n + 1 is equal to the sum of the coefficients of rth and (r + 1)th terms in the expansion of (1 + x)n.


Prove that the term independent of x in the expansion of \[\left( x + \frac{1}{x} \right)^{2n}\]  is \[\frac{1 \cdot 3 \cdot 5 . . . \left( 2n - 1 \right)}{n!} . 2^n .\]

 
 

The coefficients of 5th, 6th and 7th terms in the expansion of (1 + x)n are in A.P., find n.

 

If the coefficients of 2nd, 3rd and 4th terms in the expansion of (1 + x)2n are in A.P., show that  \[2 n^2 - 9n + 7 = 0\]

 


Find the coefficient of a4 in the product (1 + 2a)4 (2 − a)5 using binomial theorem.

 

If 3rd, 4th 5th and 6th terms in the expansion of (x + a)n be respectively a, b, c and d, prove that `(b^2 - ac)/(c^2 - bd) = (5a)/(3c)`.


If the 6th, 7th and 8th terms in the expansion of (x + a)n are respectively 112, 7 and 1/4, find xan.


Find a, b and n in the expansion of (a + b)n, if the first three terms in the expansion are 729, 7290 and 30375 respectively.


In the expansion of \[\left( x^2 - \frac{1}{3x} \right)^9\] , the term without x is equal to

 

The middle term in the expansion of \[\left( \frac{2 x^2}{3} + \frac{3}{2 x^2} \right)^{10}\] is 

 

In the expansion of \[\left( \frac{1}{2} x^{1/3} + x^{- 1/5} \right)^8\] , the term independent of x is

 

If the sum of odd numbered terms and the sum of even numbered terms in the expansion of  \[\left( x + a \right)^n\]  are A and B respectively, then the value of \[\left( x^2 - a^2 \right)^n\] is 

 

If rth term is the middle term in the expansion of \[\left( x^2 - \frac{1}{2x} \right)^{20}\]  then \[\left( r + 3 \right)^{th}\]  term is

 

 

The number of terms with integral coefficients in the expansion of \[\left( {17}^{1/3} + {35}^{1/2} x \right)^{600}\] is

 

If the term free from x in the expansion of `(sqrt(x) - k/x^2)^10` is 405, find the value of k.


Find the term independent of x in the expansion of `(3x - 2/x^2)^15`


Find the value of r, if the coefficients of (2r + 4)th and (r – 2)th terms in the expansion of (1 + x)18 are equal.


If p is a real number and if the middle term in the expansion of `(p/2 + 2)^8` is 1120, find p.


Find n in the binomial `(root(3)(2) + 1/(root(3)(3)))^n` if the ratio of 7th term from the beginning to the 7th term from the end is `1/6`


If the middle term of `(1/x + x sin x)^10` is equal to `7 7/8`, then value of x is ______.


The last two digits of the numbers 3400 are 01.


The coefficient of x256 in the expansion of (1 – x)101(x2 + x + 1)100 is ______.


The middle term in the expansion of (1 – 3x + 3x2 – x3)6 is ______.


Let the coefficients of the middle terms in the expansion of `(1/sqrt(6) + βx)^4, (1 - 3βx)^2` and `(1 - β/2x)^6, β > 0`, common difference of this A.P., then `50 - (2d)/β^2` is equal to ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×