Advertisements
Advertisements
Question
In the below fig. O is the centre of the circle. Find ∠BAC.
Advertisements
Solution
WE have `/_AOB=80°`
and ∠AOC =110°
∴∠AOB+∠AOC+∠BOC=360°
⇒80°+110°+∠BOC=360°
⇒∠BOC=360°-80°-110°
⇒∠B0C=170°
By degree measure theorem
∠BOC=2∠BAC
⇒170°=2∠BAC
⇒∠BAC=`(170°)/2=85°`
APPEARS IN
RELATED QUESTIONS
Fill in the blank:
A circle divides the plane, on which it lies, in ............ parts.
Prove that a diameter of a circle which bisects a chord of the circle also bisects the angle subtended by the chord at the centre of the circle.
If O is the centre of the circle, find the value of x in the following figure:
If O is the centre of the circle, find the value of x in the following figure
If O is the centre of the circle, find the value of x in the following figure
In the given figure, if ∠ACB = 40°, ∠DPB = 120°, find ∠CBD.
In the given figure, two circles intersect at A and B. The centre of the smaller circle is Oand it lies on the circumference of the larger circle. If ∠APB = 70°, find ∠ACB.
In the given figure, if ∠AOB = 80° and ∠ABC = 30°, then find ∠CAO.
In the given figure, AB is a diameter of the circle such that ∠A = 35° and ∠Q = 25°, find ∠PBR.
If ABC is an arc of a circle and ∠ABC = 135°, then the ratio of arc \[\stackrel\frown{ABC}\] to the circumference is ______.
