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Question
In the below fig. O is the centre of the circle. Find ∠BAC.
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Solution
WE have `/_AOB=80°`
and ∠AOC =110°
∴∠AOB+∠AOC+∠BOC=360°
⇒80°+110°+∠BOC=360°
⇒∠BOC=360°-80°-110°
⇒∠B0C=170°
By degree measure theorem
∠BOC=2∠BAC
⇒170°=2∠BAC
⇒∠BAC=`(170°)/2=85°`
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