Advertisements
Advertisements
Question
If O is the centre of the circle, find the value of x in the following figure
Advertisements
Solution
We have
∠ DBO = 40°
∠ DBC = 90°
⇒ ∠ DBO + ∠OBC = 90°
⇒ 40° + ∠OBC = 90°
⇒ ∠ OBC = 90° - 40° = 50°
By degree measure theorem
ÐAOC = 2ÐOBC
⇒ x = 2´ 50° = 100°
APPEARS IN
RELATED QUESTIONS
In the below fig. O is the centre of the circle. Find ∠BAC.
If O is the centre of the circle, find the value of x in the following figure:
If O is the centre of the circle, find the value of x in the following figures.
In the given figure, O is the centre of the circle, BO is the bisector of ∠ABC. Show that AB = BC.
In the given figure, O and O' are centres of two circles intersecting at B and C. ACD is a straight line, find x.
In the given figure, if ∠ACB = 40°, ∠DPB = 120°, find ∠CBD.
In the given figure, O is the centre of the circle, prove that ∠x = ∠y + ∠z.
In the given figure, A is the centre of the circle. ABCD is a parallelogram and CDE is a straight line. Find ∠BCD : ∠ABE.
In the given figure, P and Q are centres of two circles intersecting at B and C. ACD is a straight line. Then, ∠BQD =
The chord of a circle is equal to its radius. The angle subtended by this chord at the minor arc of the circle is
