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Question
If O is the centre of the circle, find the value of x in the following figure
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Solution
In ΔDAB by angle sum property
∠ADB + ∠DAB + ∠ABD = 180°
⇒ 32° + ∠DAB + 50° = 180°
⇒ ∠DAB = 180° - 32° - 50° = 98°
Now,
∠CAB + ∠DAB = 180° ...(Opposite angles of cyclic quadrilateral)
⇒ 98° + x = 180°
⇒ x = 180° - 98° = 82°
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