Advertisements
Advertisements
Question
In the given figure, O and O' are centres of two circles intersecting at B and C. ACD is a straight line, find x.

Advertisements
Solution
It is given that
Two circles having center O and O' and ∠AOB = 130°
And AC is diameter of circle having center O

We have
`angle ACB =1/2 angleAOB = 65°`
So
`angleDCB = 180° - angleACB`
= 180° - 65°
= 115°
Now, reflex `angleBO'D = 2 angleBCD`
So
`360° - x° = 2 xx 115 `
= 230°
APPEARS IN
RELATED QUESTIONS
In the given figure, A, B, C and D are four points on a circle. AC and BD intersect at a point E such that ∠BEC = 130° and ∠ECD = 20°. Find ∠BAC.

In the below fig. O is the centre of the circle. Find ∠BAC.

If O is the centre of the circle, find the value of x in the following figure:

If O is the centre of the circle, find the value of x in the following figure

If O is the centre of the circle, find the value of x in the following figure

If O is the centre of the circle, find the value of x in the following figures.

O is the circumcentre of the triangle ABC and OD is perpendicular on BC. Prove that ∠BOD = ∠A.
In the given figure, two circles intersect at A and B. The centre of the smaller circle is Oand it lies on the circumference of the larger circle. If ∠APB = 70°, find ∠ACB.

In the given figure, P and Q are centres of two circles intersecting at B and C. ACD is a straight line. Then, ∠BQD =

In the given figure, if O is the circumcentre of ∠ABC, then find the value of ∠OBC + ∠BAC.

