Advertisements
Advertisements
Question
In the given figure, A, B, C and D are four points on a circle. AC and BD intersect at a point E such that ∠BEC = 130° and ∠ECD = 20°. Find ∠BAC.
Advertisements
Solution
In ΔCDE,
∠CDE + ∠DCE = ∠CEB ...(Exterior angle)
⇒ ∠CDE + 20° = 130°
⇒ ∠CDE = 110°
However, ∠BAC = ∠CDE ...(Angles in the same segment of a circle)
⇒ ∠BAC = 110°
APPEARS IN
RELATED QUESTIONS
Fill in the blank:
A circle divides the plane, on which it lies, in ............ parts.
In the below fig. O is the centre of the circle. Find ∠BAC.
If O is the centre of the circle, find the value of x in the following figure
If O is the centre of the circle, find the value of x in the following figure
If O is the centre of the circle, find the value of x in the following figure
If O is the centre of the circle, find the value of x in the following figures.
In the given figure, if ∠ACB = 40°, ∠DPB = 120°, find ∠CBD.
In the given figure, it is given that O is the centre of the circle and ∠AOC = 150°. Find ∠ABC.
In the given figure, O is the centre of the circle, prove that ∠x = ∠y + ∠z.
In the given figure, if O is the circumcentre of ∠ABC, then find the value of ∠OBC + ∠BAC.
