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Question
In the given figure, ∠ABC = 69°, ∠ACB = 31°, find ∠BDC.
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Solution
In ΔABC,
∠BAC + ∠ABC + ∠ACB = 180° ...(Angle sum property of a triangle)
⇒ ∠BAC + 69° + 31° = 180°
⇒ ∠BAC = 180° − 100º
⇒ ∠BAC = 80°
∠BDC = ∠BAC = 80° ...(Angles in the same segment of a circle are equal)
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