Advertisements
Advertisements
Question
If O is the centre of the circle, find the value of x in the following figure
Advertisements
Solution
We have
∠OAB = 35°
Then, ∠OBA = ∠OAB = 35°
In ∠AOB, by angle sum property
⇒∠AOB + ∠OAB + ∠OBA = 180°
⇒ ∠AOB = 180° - 35° - 35° = 110°
∴∠AOB + reflex ∠AOB = 360°
⇒ 110° + reflex ∠AOB = 360°
⇒ reflex ∠AOB = 360° -110° = 250°
By degree measure theorem reflex ∠AOB = 2
⇒250° = 2x
`⇒ x =( 250°)/2= 125°`
APPEARS IN
RELATED QUESTIONS
In the given figure, ∠ABC = 69°, ∠ACB = 31°, find ∠BDC.
Fill in the blank:
Segment of a circle is the region between an arc and .................. of the circle.
Prove that a diameter of a circle which bisects a chord of the circle also bisects the angle subtended by the chord at the centre of the circle.
Given an arc of a circle, complete the circle.
In the given figure, O is the centre of the circle, BO is the bisector of ∠ABC. Show that AB = BC.
In the given figure, if ∠AOB = 80° and ∠ABC = 30°, then find ∠CAO.
In the given figure, AB is a diameter of the circle such that ∠A = 35° and ∠Q = 25°, find ∠PBR.
If the given figure, AOC is a diameter of the circle and arc AXB = \[\frac{1}{2}\] arc BYC. Find ∠BOC.
In a circle, the major arc is 3 times the minor arc. The corresponding central angles and the degree measures of two arcs are
A circle has radius `sqrt(2)` cm. It is divided into two segments by a chord of length 2 cm. Prove that the angle subtended by the chord at a point in major segment is 45°.
