Advertisements
Advertisements
Question
In the given figure, if ∠ACB = 40°, ∠DPB = 120°, find ∠CBD.
Advertisements
Solution
It is given that ∠ACB = 40° and ∠DPB = 120°
Construction: Join the point A and B
`angle ACB = angleADB = 40°` (Angle in the same segment)
Now in \[\bigtriangleup BDP\] we have
\[\angle DPB + \angle PBD + \angle BDP = 180° \]
\[ \Rightarrow 120° + \angle PBD + 40° = 180° \]
\[ \Rightarrow \angle PBD = 20° \]
Hence `angle CBD = 20° `
APPEARS IN
RELATED QUESTIONS
Prove that the line joining the mid-point of a chord to the centre of the circle passes through the mid-point of the corresponding minor arc.
In the below fig. O is the centre of the circle. Find ∠BAC.
If O is the centre of the circle, find the value of x in the following figure:
If O is the centre of the circle, find the value of x in the following figure
If O is the centre of the circle, find the value of x in the following figure
In the given figure, AB is a diameter of the circle such that ∠A = 35° and ∠Q = 25°, find ∠PBR.
If the given figure, AOC is a diameter of the circle and arc AXB = \[\frac{1}{2}\] arc BYC. Find ∠BOC.
If ABC is an arc of a circle and ∠ABC = 135°, then the ratio of arc \[\stackrel\frown{ABC}\] to the circumference is ______.
A chord of a circle is equal to its radius. Find the angle subtended by this chord at a point in major segment.
A circle has radius `sqrt(2)` cm. It is divided into two segments by a chord of length 2 cm. Prove that the angle subtended by the chord at a point in major segment is 45°.
