Advertisements
Advertisements
Question
If O is the centre of the circle, find the value of x in the following figure
Advertisements
Solution
We have
∠AOC = 120°
By degree measure theorem
∠AOC = 2∠APC
⇒ 120° = 2∠APC
⇒∠APC= `(120°)/2=60°`
∴∠APC + ∠ABC = 180°
⇒ 60° + ∠ABC = 180°
⇒ -60° +180° = ∠ABC
⇒ ∠ABC = 120°
∴∠ABC + ∠DBC = 180°
⇒120 + x = 180°
⇒ x = 180° -120° = 60°
APPEARS IN
RELATED QUESTIONS
In the given figure, A, B, C and D are four points on a circle. AC and BD intersect at a point E such that ∠BEC = 130° and ∠ECD = 20°. Find ∠BAC.
Fill in the blank:
Segment of a circle is the region between an arc and .................. of the circle.
If O is the centre of the circle, find the value of x in the following figure:
If O is the centre of the circle, find the value of x in the following figure
If O is the centre of the circle, find the value of x in the following figure
In the given figure, O is the centre of the circle, BO is the bisector of ∠ABC. Show that AB = BC.
In the given figure, it is given that O is the centre of the circle and ∠AOC = 150°. Find ∠ABC.
Prove that the line segment joining the mid-point of the hypotenuse of a right triangle to its opposite vertex is half the hypotenuse.
In a circle, the major arc is 3 times the minor arc. The corresponding central angles and the degree measures of two arcs are
A chord of a circle is equal to its radius. Find the angle subtended by this chord at a point in major segment.
