Advertisements
Advertisements
Question
If O is the centre of the circle, find the value of x in the following figure

Advertisements
Solution
We have
∠AOC = 120°
By degree measure theorem
∠AOC = 2∠APC
⇒ 120° = 2∠APC
⇒∠APC= `(120°)/2=60°`
∴∠APC + ∠ABC = 180°
⇒ 60° + ∠ABC = 180°
⇒ -60° +180° = ∠ABC
⇒ ∠ABC = 120°
∴∠ABC + ∠DBC = 180°
⇒120 + x = 180°
⇒ x = 180° -120° = 60°
APPEARS IN
RELATED QUESTIONS
Prove that a diameter of a circle which bisects a chord of the circle also bisects the angle subtended by the chord at the centre of the circle.
If O is the centre of the circle, find the value of x in the following figure

If O is the centre of the circle, find the value of x in the following figure

O is the circumcentre of the triangle ABC and OD is perpendicular on BC. Prove that ∠BOD = ∠A.
In the given figure, O is the centre of the circle, BO is the bisector of ∠ABC. Show that AB = BC.

Prove that the angle in a segment shorter than a semicircle is greater than a right angle.
Prove that the angle in a segment greater than a semi-circle is less than a right angle.
In the given figure, AB is a diameter of the circle such that ∠A = 35° and ∠Q = 25°, find ∠PBR.

In the given figure, P and Q are centres of two circles intersecting at B and C. ACD is a straight line. Then, ∠BQD =

If ABC is an arc of a circle and ∠ABC = 135°, then the ratio of arc \[\stackrel\frown{ABC}\] to the circumference is ______.
