Advertisements
Advertisements
Question
If O is the centre of the circle, find the value of x in the following figure:

Advertisements
Solution
∠AOC= 135°
∴∠AOC+ ∠BOC -180°
⇒ 135° + ∠BOC = 180°
⇒∠BOC = 180° -135° = 45°
By degree measures theorem
∠BOC = 2∠CDB
⇒ 45° = 2x
`⇒x=(45°)/2=22(1°)/2.`
APPEARS IN
RELATED QUESTIONS
Prove that a diameter of a circle which bisects a chord of the circle also bisects the angle subtended by the chord at the centre of the circle.
Given an arc of a circle, show how to complete the circle.
If O is the centre of the circle, find the value of x in the following figure:

If O is the centre of the circle, find the value of x in the following figure

If O is the centre of the circle, find the value of x in the following figures.

In the given figure, O and O' are centres of two circles intersecting at B and C. ACD is a straight line, find x.

In the given figure, O is the centre of the circle, prove that ∠x = ∠y + ∠z.

In the given figure, AB is a diameter of the circle such that ∠A = 35° and ∠Q = 25°, find ∠PBR.

In the given figure, if O is the circumcentre of ∠ABC, then find the value of ∠OBC + ∠BAC.

In the following figure, ∠ACB = 40º. Find ∠OAB.

