Advertisements
Advertisements
Question
If O is the centre of the circle, find the value of x in the following figure:
Advertisements
Solution
∠AOC= 135°
∴∠AOC+ ∠BOC -180°
⇒ 135° + ∠BOC = 180°
⇒∠BOC = 180° -135° = 45°
By degree measures theorem
∠BOC = 2∠CDB
⇒ 45° = 2x
`⇒x=(45°)/2=22(1°)/2.`
APPEARS IN
RELATED QUESTIONS
In the given figure, A, B, C and D are four points on a circle. AC and BD intersect at a point E such that ∠BEC = 130° and ∠ECD = 20°. Find ∠BAC.
Fill in the blank:
Segment of a circle is the region between an arc and .................. of the circle.
If O is the centre of the circle, find the value of x in the following figure
If O is the centre of the circle, find the value of x in the following figure
If O is the centre of the circle, find the value of x in the following figures.
O is the circumcentre of the triangle ABC and OD is perpendicular on BC. Prove that ∠BOD = ∠A.
In the given figure, if ∠ACB = 40°, ∠DPB = 120°, find ∠CBD.
In the given figure, O is the centre of the circle, prove that ∠x = ∠y + ∠z.
Prove that the line segment joining the mid-point of the hypotenuse of a right triangle to its opposite vertex is half the hypotenuse.
If the given figure, AOC is a diameter of the circle and arc AXB = \[\frac{1}{2}\] arc BYC. Find ∠BOC.
