Advertisements
Advertisements
प्रश्न
In the given figure, A, B, C and D are four points on a circle. AC and BD intersect at a point E such that ∠BEC = 130° and ∠ECD = 20°. Find ∠BAC.
Advertisements
उत्तर
In ΔCDE,
∠CDE + ∠DCE = ∠CEB ...(Exterior angle)
⇒ ∠CDE + 20° = 130°
⇒ ∠CDE = 110°
However, ∠BAC = ∠CDE ...(Angles in the same segment of a circle)
⇒ ∠BAC = 110°
APPEARS IN
संबंधित प्रश्न
In the below fig. O is the centre of the circle. Find ∠BAC.
If O is the centre of the circle, find the value of x in the following figure
If O is the centre of the circle, find the value of x in the following figure
If O is the centre of the circle, find the value of x in the following figure
If O is the centre of the circle, find the value of x in the following figure
If O is the centre of the circle, find the value of x in the following figures.
In the given figure, P and Q are centres of two circles intersecting at B and C. ACD is a straight line. Then, ∠BQD =
In the given figure, if O is the circumcentre of ∠ABC, then find the value of ∠OBC + ∠BAC.
A chord of a circle is equal to its radius. Find the angle subtended by this chord at a point in major segment.
In the following figure, AB and CD are two chords of a circle intersecting each other at point E. Prove that ∠AEC = `1/2` (Angle subtended by arc CXA at centre + angle subtended by arc DYB at the centre).
