Advertisements
Advertisements
प्रश्न
If O is the centre of the circle, find the value of x in the following figure
Advertisements
उत्तर
In DDAB, by angle sum property
∠ADB + ∠DAB + ∠ABD = 180°
⇒ 32° + ∠DAB + 50° = 180°
⇒ ∠OAB = 180° - 32° - 50°
⇒ ∠DAB = 95°
Now,
∠OAB + ∠DCB = 180°
∠ 98 + x = 180°
⇒ x = 180 - 98° = 82°
APPEARS IN
संबंधित प्रश्न
If O is the centre of the circle, find the value of x in the following figure:
If O is the centre of the circle, find the value of x in the following figure:
If O is the centre of the circle, find the value of x in the following figure
If O is the centre of the circle, find the value of x in the following figure
O is the circumcentre of the triangle ABC and OD is perpendicular on BC. Prove that ∠BOD = ∠A.
In the given figure, O and O' are centres of two circles intersecting at B and C. ACD is a straight line, find x.
In the given figure, if ∠ACB = 40°, ∠DPB = 120°, find ∠CBD.
Prove that the angle in a segment shorter than a semicircle is greater than a right angle.
In the given figure, A is the centre of the circle. ABCD is a parallelogram and CDE is a straight line. Find ∠BCD : ∠ABE.
In the given figure, AB is a diameter of the circle such that ∠A = 35° and ∠Q = 25°, find ∠PBR.
