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Question
If O is the centre of the circle, find the value of x in the following figure
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Solution
In DDAB, by angle sum property
∠ADB + ∠DAB + ∠ABD = 180°
⇒ 32° + ∠DAB + 50° = 180°
⇒ ∠OAB = 180° - 32° - 50°
⇒ ∠DAB = 95°
Now,
∠OAB + ∠DCB = 180°
∠ 98 + x = 180°
⇒ x = 180 - 98° = 82°
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