Advertisements
Advertisements
प्रश्न
If O is the centre of the circle, find the value of x in the following figure
Advertisements
उत्तर
We have
∠ DBO = 40°
∠ DBC = 90°
⇒ ∠ DBO + ∠OBC = 90°
⇒ 40° + ∠OBC = 90°
⇒ ∠ OBC = 90° - 40° = 50°
By degree measure theorem
ÐAOC = 2ÐOBC
⇒ x = 2´ 50° = 100°
APPEARS IN
संबंधित प्रश्न
In the given figure, ∠ABC = 69°, ∠ACB = 31°, find ∠BDC.
Fill in the blank:
A circle divides the plane, on which it lies, in ............ parts.
Prove that the line joining the mid-point of a chord to the centre of the circle passes through the mid-point of the corresponding minor arc.
If O is the centre of the circle, find the value of x in the following figure
If O is the centre of the circle, find the value of x in the following figure
O is the circumcentre of the triangle ABC and OD is perpendicular on BC. Prove that ∠BOD = ∠A.
In the given figure, if ∠ACB = 40°, ∠DPB = 120°, find ∠CBD.
In the given figure, it is given that O is the centre of the circle and ∠AOC = 150°. Find ∠ABC.
In the given figure, O is the centre of a circle and PQ is a diameter. If ∠ROS = 40°, find ∠RTS.
In the given figure, two circles intersect at A and B. The centre of the smaller circle is Oand it lies on the circumference of the larger circle. If ∠APB = 70°, find ∠ACB.
