Advertisements
Advertisements
प्रश्न
If O is the centre of the circle, find the value of x in the following figure:
Advertisements
उत्तर
We have
∠ABC = 40°
∠ACB = 90°
In ∠ABC, by angle sum property
∠CAB + ∠ACB + ∠ABC = 180°
⇒ ∠CAB + 90° + 40° = 180°
⇒ ∠CAB = 180° - 90°
⇒ ∠CAB = 50°
Now,
⇒COB = ∠CAB
⇒x = 50°
APPEARS IN
संबंधित प्रश्न
Prove that a diameter of a circle which bisects a chord of the circle also bisects the angle subtended by the chord at the centre of the circle.
Given an arc of a circle, show how to complete the circle.
If O is the centre of the circle, find the value of x in the following figure
O is the circumcentre of the triangle ABC and OD is perpendicular on BC. Prove that ∠BOD = ∠A.
In the given figure, it is given that O is the centre of the circle and ∠AOC = 150°. Find ∠ABC.
In the given figure, O is the centre of a circle and PQ is a diameter. If ∠ROS = 40°, find ∠RTS.
In the given figure, if ∠AOB = 80° and ∠ABC = 30°, then find ∠CAO.
In the given figure, if O is the circumcentre of ∠ABC, then find the value of ∠OBC + ∠BAC.
The chord of a circle is equal to its radius. The angle subtended by this chord at the minor arc of the circle is
A chord of a circle is equal to its radius. Find the angle subtended by this chord at a point in major segment.
