Advertisements
Advertisements
प्रश्न
If O is the centre of the circle, find the value of x in the following figure:
Advertisements
उत्तर
We have
∠ABC = 40°
∠ACB = 90°
In ∠ABC, by angle sum property
∠CAB + ∠ACB + ∠ABC = 180°
⇒ ∠CAB + 90° + 40° = 180°
⇒ ∠CAB = 180° - 90°
⇒ ∠CAB = 50°
Now,
⇒COB = ∠CAB
⇒x = 50°
APPEARS IN
संबंधित प्रश्न
Given an arc of a circle, complete the circle.
If O is the centre of the circle, find the value of x in the following figure
In the given figure, O and O' are centres of two circles intersecting at B and C. ACD is a straight line, find x.
In the given figure, if ∠ACB = 40°, ∠DPB = 120°, find ∠CBD.
Prove that the angle in a segment shorter than a semicircle is greater than a right angle.
Prove that the angle in a segment greater than a semi-circle is less than a right angle.
Prove that the line segment joining the mid-point of the hypotenuse of a right triangle to its opposite vertex is half the hypotenuse.
In the given figure, if ∠AOB = 80° and ∠ABC = 30°, then find ∠CAO.
In the given figure, AB is a diameter of the circle such that ∠A = 35° and ∠Q = 25°, find ∠PBR.
If the given figure, AOC is a diameter of the circle and arc AXB = \[\frac{1}{2}\] arc BYC. Find ∠BOC.
