Advertisements
Advertisements
प्रश्न
In the below fig. O is the centre of the circle. Find ∠BAC.
Advertisements
उत्तर
WE have `/_AOB=80°`
and ∠AOC =110°
∴∠AOB+∠AOC+∠BOC=360°
⇒80°+110°+∠BOC=360°
⇒∠BOC=360°-80°-110°
⇒∠B0C=170°
By degree measure theorem
∠BOC=2∠BAC
⇒170°=2∠BAC
⇒∠BAC=`(170°)/2=85°`
APPEARS IN
संबंधित प्रश्न
Fill in the blank:
Segment of a circle is the region between an arc and .................. of the circle.
If O is the centre of the circle, find the value of x in the following figure:
If O is the centre of the circle, find the value of x in the following figure
If O is the centre of the circle, find the value of x in the following figure
Prove that the angle in a segment shorter than a semicircle is greater than a right angle.
Prove that the angle in a segment greater than a semi-circle is less than a right angle.
In the given figure, two circles intersect at A and B. The centre of the smaller circle is Oand it lies on the circumference of the larger circle. If ∠APB = 70°, find ∠ACB.
In the given figure, if ∠AOB = 80° and ∠ABC = 30°, then find ∠CAO.
In the given figure, A is the centre of the circle. ABCD is a parallelogram and CDE is a straight line. Find ∠BCD : ∠ABE.
A chord of a circle is equal to its radius. Find the angle subtended by this chord at a point in major segment.
