Advertisements
Advertisements
प्रश्न
If the given figure, AOC is a diameter of the circle and arc AXB = \[\frac{1}{2}\] arc BYC. Find ∠BOC.
Advertisements
उत्तर
We need to find `angle BOC`
\[\text{ arc } AXB = \frac{1}{2}\text{ arc} BYC, \]
\[\angle AOB = \frac{1}{2}\angle BOC\]
\[\text{ Also } \angle AOB + \angle BOC = 180°\]
\[\text{ Therefore, } \frac{1}{2}\angle BOC + \angle BOC = 180° \]
\[ \Rightarrow \angle BOC = \frac{2}{3} \times 180°= 120°\]
APPEARS IN
संबंधित प्रश्न
If O is the centre of the circle, find the value of x in the following figure
If O is the centre of the circle, find the value of x in the following figure
If O is the centre of the circle, find the value of x in the following figures.
If O is the centre of the circle, find the value of x in the following figures.
O is the circumcentre of the triangle ABC and OD is perpendicular on BC. Prove that ∠BOD = ∠A.
Prove that the angle in a segment shorter than a semicircle is greater than a right angle.
Prove that the angle in a segment greater than a semi-circle is less than a right angle.
In the given figure, A is the centre of the circle. ABCD is a parallelogram and CDE is a straight line. Find ∠BCD : ∠ABE.
If ABC is an arc of a circle and ∠ABC = 135°, then the ratio of arc \[\stackrel\frown{ABC}\] to the circumference is ______.
In the following figure, AB and CD are two chords of a circle intersecting each other at point E. Prove that ∠AEC = `1/2` (Angle subtended by arc CXA at centre + angle subtended by arc DYB at the centre).
