Advertisements
Advertisements
प्रश्न
If the given figure, AOC is a diameter of the circle and arc AXB = \[\frac{1}{2}\] arc BYC. Find ∠BOC.
Advertisements
उत्तर
We need to find `angle BOC`
\[\text{ arc } AXB = \frac{1}{2}\text{ arc} BYC, \]
\[\angle AOB = \frac{1}{2}\angle BOC\]
\[\text{ Also } \angle AOB + \angle BOC = 180°\]
\[\text{ Therefore, } \frac{1}{2}\angle BOC + \angle BOC = 180° \]
\[ \Rightarrow \angle BOC = \frac{2}{3} \times 180°= 120°\]
APPEARS IN
संबंधित प्रश्न
In the below fig. O is the centre of the circle. Find ∠BAC.
If O is the centre of the circle, find the value of x in the following figure:
If O is the centre of the circle, find the value of x in the following figure
If O is the centre of the circle, find the value of x in the following figures.
Prove that the angle in a segment greater than a semi-circle is less than a right angle.
In the given figure, two circles intersect at A and B. The centre of the smaller circle is Oand it lies on the circumference of the larger circle. If ∠APB = 70°, find ∠ACB.
In the given figure, if O is the circumcentre of ∠ABC, then find the value of ∠OBC + ∠BAC.
If arcs AXB and CYD of a circle are congruent, find the ratio of AB and CD.
A chord of a circle is equal to its radius. Find the angle subtended by this chord at a point in major segment.
In the following figure, AB and CD are two chords of a circle intersecting each other at point E. Prove that ∠AEC = `1/2` (Angle subtended by arc CXA at centre + angle subtended by arc DYB at the centre).
