Advertisements
Advertisements
प्रश्न
In the given figure, if O is the circumcentre of ∠ABC, then find the value of ∠OBC + ∠BAC.

Advertisements
उत्तर

Since, O is the circumcentre of \[\bigtriangleup ABC\], So, O would be centre of the circle passing through points A, B and C.
As OA = OB (Radii of the same circle)
\[\therefore \angle OAB = \angle OBA \left( \text{ Angle opposite to equal sides are equal } \right)\]
\[\text{ or } , \angle BAC = \angle OBA\]
\[\text{ From } \left( 1 \right)\]
\[\angle BAC + \angle OBC = 90°\]
APPEARS IN
संबंधित प्रश्न
In the given figure, ∠ABC = 69°, ∠ACB = 31°, find ∠BDC.

Fill in the blank:
Segment of a circle is the region between an arc and .................. of the circle.
Prove that a diameter of a circle which bisects a chord of the circle also bisects the angle subtended by the chord at the centre of the circle.
If O is the centre of the circle, find the value of x in the following figure:

If O is the centre of the circle, find the value of x in the following figure

O is the circumcentre of the triangle ABC and OD is perpendicular on BC. Prove that ∠BOD = ∠A.
Prove that the line segment joining the mid-point of the hypotenuse of a right triangle to its opposite vertex is half the hypotenuse.
In a circle, the major arc is 3 times the minor arc. The corresponding central angles and the degree measures of two arcs are
The chord of a circle is equal to its radius. The angle subtended by this chord at the minor arc of the circle is
A circle has radius `sqrt(2)` cm. It is divided into two segments by a chord of length 2 cm. Prove that the angle subtended by the chord at a point in major segment is 45°.
