Advertisements
Advertisements
प्रश्न
If O is the centre of the circle, find the value of x in the following figure

Advertisements
उत्तर
We have
∠ DBO = 40°
∠ DBC = 90°
⇒ ∠ DBO + ∠OBC = 90°
⇒ 40° + ∠OBC = 90°
⇒ ∠ OBC = 90° - 40° = 50°
By degree measure theorem
ÐAOC = 2ÐOBC
⇒ x = 2´ 50° = 100°
APPEARS IN
संबंधित प्रश्न
If O is the centre of the circle, find the value of x in the following figure

If O is the centre of the circle, find the value of x in the following figure

O is the circumcentre of the triangle ABC and OD is perpendicular on BC. Prove that ∠BOD = ∠A.
In the given figure, O is the centre of the circle, BO is the bisector of ∠ABC. Show that AB = BC.

In the given figure, O is the centre of the circle, prove that ∠x = ∠y + ∠z.

In the given figure, O is the centre of a circle and PQ is a diameter. If ∠ROS = 40°, find ∠RTS.

In the given figure, two circles intersect at A and B. The centre of the smaller circle is Oand it lies on the circumference of the larger circle. If ∠APB = 70°, find ∠ACB.

The chord of a circle is equal to its radius. The angle subtended by this chord at the minor arc of the circle is
If arcs AXB and CYD of a circle are congruent, find the ratio of AB and CD.
In the following figure, ∠ACB = 40º. Find ∠OAB.

