Advertisements
Advertisements
प्रश्न
Given an arc of a circle, complete the circle.
Advertisements
उत्तर

Steps of construction:
(i) Take three point A, B, C on the given Arc
(ii) Join AB and BC
(iii) Draw the perpendicular bisectors of chords AB and BC which interest each other at
point O, then O will required center of the required circle
(iv) Join OA
(v) With center O and radius OA, complete the circle
APPEARS IN
संबंधित प्रश्न
In the given figure, ∠ABC = 69°, ∠ACB = 31°, find ∠BDC.

Prove that a diameter of a circle which bisects a chord of the circle also bisects the angle subtended by the chord at the centre of the circle.
If O is the centre of the circle, find the value of x in the following figure

In the given figure, O is the centre of the circle, BO is the bisector of ∠ABC. Show that AB = BC.

In the given figure, if ∠ACB = 40°, ∠DPB = 120°, find ∠CBD.

In the given figure, O is the centre of a circle and PQ is a diameter. If ∠ROS = 40°, find ∠RTS.

Prove that the angle in a segment shorter than a semicircle is greater than a right angle.
In the given figure, if O is the circumcentre of ∠ABC, then find the value of ∠OBC + ∠BAC.

The chord of a circle is equal to its radius. The angle subtended by this chord at the minor arc of the circle is
A circle has radius `sqrt(2)` cm. It is divided into two segments by a chord of length 2 cm. Prove that the angle subtended by the chord at a point in major segment is 45°.
