Advertisements
Advertisements
प्रश्न
Suppose You Are Given a Circle. Give a Construction to Find Its Centre.
Advertisements
उत्तर
Steps of constructions:
(1) Take three point A, B and C the given circle
(2) Join AB and BC
(3) Draw the perpendicular bisectors of chord AB and BC which intersect each other at O.
(4) Point O will be the required center of the circle because we know that the perpendicular
bisector of the cord always passes through the center
APPEARS IN
संबंधित प्रश्न
O is the center of a circle of radius 8cm. The tangent at a point A on the circle cuts a line through O at B such that AB = 15 cm. Find OB
In Fig. 1, PA and PB are two tangents drawn from an external point P to a circle with centre C and radius 4 cm. If PA ⊥ PB, then the length of each tangent is:
In the given figure, ΔABC is an equilateral triangle. Find m∠BEC.
In the given figure, O is the centre of a circle, chord PQ ≅ chord RS If ∠ POR = 70° and (arc RS) = 80°, find –
(1) m(arc PR)
(2) m(arc QS)
(3) m(arc QSR)
A chord is at a distance of 15 cm from the centre of the circle of radius 25 cm. The length of the chord is
If a hexagon ABCDEF circumscribe a circle, prove that AB + CD + EF = BC + DE + FA.
If A, B, C, D are four points such that ∠BAC = 30° and ∠BDC = 60°, then D is the centre of the circle through A, B and C.
If two chords AB and CD of a circle AYDZBWCX intersect at right angles (see figure), prove that arc CXA + arc DZB = arc AYD + arc BWC = semi-circle.
In the following figure, O is the centre of the circle. Name a chord, which is not the diameter of the circle.
What is the fixed point inside the circle called?
