Advertisements
Advertisements
प्रश्न
Suppose You Are Given a Circle. Give a Construction to Find Its Centre.
Advertisements
उत्तर

Steps of constructions:
(1) Take three point A, B and C the given circle
(2) Join AB and BC
(3) Draw the perpendicular bisectors of chord AB and BC which intersect each other at O.
(4) Point O will be the required center of the circle because we know that the perpendicular
bisector of the cord always passes through the center
APPEARS IN
संबंधित प्रश्न
In Fig. 8, O is the centre of a circle of radius 5 cm. T is a point such that OT = 13 cm and OT intersects circle at E. If AB is a tangent to the circle at E, find the length of AB, where TP and TQ are two tangents to the circle.

Two tangents TP and TQ are drawn to a circle with centre O from an external point T. Prove that ∠PTQ = 2∠OPQ.

If the difference between the circumference and the radius of a circle is 37 cm, then using`22/7`, the circumference (in cm) of the circle is:
Tangents PA and PB are drawn from an external point P to two concentric circles with centre O and radii 8 cm and 5 cm respectively, as shown in Fig. 3. If AP = 15 cm, then find the length of BP.

Use the figure given below to fill in the blank:
If PQ is 8 cm long, the length of RS = ________

Draw a circle of diameter 7 cm. Draw two radii of this circle such that the angle between these radii is 90°. Shade the minor sector obtained. Write a special name for this sector.
State, if the following statement is true or false:
Every diameter bisects a circle and each part of the circle so obtained is a semi-circle.
If the radii of two concentric circles are 4 cm and 5 cm, then the length of each chord of one circle which is tangent to the other circle is ______.
The length of tangent from an external point on a circle is always greater than the radius of the circle.
If ABC is an equilateral triangle inscribed in a circle and P be any point on the minor arc BC which does not coincide with B or C, prove that PA is angle bisector of ∠BPC.
