Advertisements
Advertisements
प्रश्न
In the given figure, ΔABC is an equilateral triangle. Find m∠BEC.

Advertisements
उत्तर
It is given that, Δ ABC is an equilateral triangle

We have to find `m angle BEC`
Since Δ ABC is an equilateral triangle.
So `angle A + angle B + angle C = 180°`
And
`angle A = angleB = angleC` = 60° …… (1)
Since, quadrilateral BACE is a cyclic qualdrilateral
So , `angle A + angleE = 180°` (Sum of opposite angles of cyclic quadrilateral is 180° .)
`60° + angle E = 180°`
`angle E = 120°`
Hence
`m angle BEC = 120°`
APPEARS IN
संबंधित प्रश्न
Fill in the blank:
A point whose distance from the centre of a circle is greater than its radius lies in ..................... of the circle.
Draw different pairs of circles. How many points does each pair have in common? What is the maximum number of common points?
In the given figure, PA and PB are two tangents to the circle with centre O. If ∠APB = 60° then find the measure of ∠OAB.

If the area of a circle is equal to sum of the areas of two circles of diameters 10 cm and 24 cm, then the diameter of the larger circle (in cm) is:
AB is a chord of a circle with centre O , AOC is a diameter and AT is the tangent at A as shown in Fig . 10.70. Prove that \[\angle\]BAT = \[\angle\] ACB.
Use the figure given below to fill in the blank:
EF is a ______ of the circle.

The ratio between the circumference and diameter of any circle is _______
C(O, r1) and C(O, r2) are two concentric circles with r1 > r2 AB is a chord of C(O, r1) touching C(O, r2) at C then ______
If a hexagon ABCDEF circumscribe a circle, prove that AB + CD + EF = BC + DE + FA.
If an are subtends an angle of 90° at the centre of a circle, then the ratio of its length to the circumference of the circle is ______.
