Advertisements
Advertisements
प्रश्न
Suppose You Are Given a Circle. Give a Construction to Find Its Centre.
Advertisements
उत्तर

Steps of constructions:
(1) Take three point A, B and C the given circle
(2) Join AB and BC
(3) Draw the perpendicular bisectors of chord AB and BC which intersect each other at O.
(4) Point O will be the required center of the circle because we know that the perpendicular
bisector of the cord always passes through the center
APPEARS IN
संबंधित प्रश्न
Prove that the line segment joining the points of contact of two parallel tangents of a circle, passes through its centre.
In the below fig. O is the centre of the circle. If ∠APB = 50°, find ∠AOB and ∠OAB.

A circle is inscribed in a ΔABC touching AB, BC and AC at P, Q and R respectively. If AB = 10 cm, AR = 7 cm and CR = 5 cm, find the length of BC.

Prove that the line segment joining the points of contact of two parallel tangents of a circle, passes through its centre.
The radius of a circle is 6 cm. The perpendicular distance from the centre of the circle to the chord which is 8 cm in length, is
Draw a circle of radius of 4.2 cm. Mark its center as O. Takes a point A on the circumference of the circle. Join AO and extend it till it meets point B on the circumference of the circle,
(i) Measure the length of AB.
(ii) Assign a special name to AB.
Find the diameter of the circle
Radius = 10 cm
In figure, AB is a chord of the circle and AOC is its diameter such that ∠ACB = 50°. If AT is the tangent to the circle at point A, then ∠BAT is equal to ______.

If a number of circles touch a given line segment PQ at a point A, then their centres lie on the perpendicular bisector of PQ.
A circle of radius 3 cm can be drawn through two points A, B such that AB = 6 cm.
