Advertisements
Advertisements
प्रश्न
In the given figure, it is given that O is the centre of the circle and ∠AOC = 150°. Find ∠ABC.
Advertisements
उत्तर
It is given that O is the centre of circle and A, B and C are points on circumference.
`angle AOC = 150°` (Given)
We have to find ∠ABC
The angle subtended by an arc of a circle at the centre is double the angle subtended by it at any point on the remaining part of the circle.
\[\angle ABC = \frac{1}{2}\left( \text{ reflex } \angle AOC \right)\]
\[ = \frac{1}{2}\left( 360° - 150° \right)\]
\[ = \frac{1}{2} \times 210° \]
\[ = 105° \]
Hence,`angle ABC = 105°`
APPEARS IN
संबंधित प्रश्न
If O is the centre of the circle, find the value of x in the following figure
If O is the centre of the circle, find the value of x in the following figures.
In the given figure, O is the centre of a circle and PQ is a diameter. If ∠ROS = 40°, find ∠RTS.
Prove that the line segment joining the mid-point of the hypotenuse of a right triangle to its opposite vertex is half the hypotenuse.
In the given figure, two congruent circles with centres O and O' intersect at A and B. If ∠AOB = 50°, then find ∠APB.
In the given figure, A is the centre of the circle. ABCD is a parallelogram and CDE is a straight line. Find ∠BCD : ∠ABE.
In the given figure, if O is the circumcentre of ∠ABC, then find the value of ∠OBC + ∠BAC.
In a circle, the major arc is 3 times the minor arc. The corresponding central angles and the degree measures of two arcs are
If ABC is an arc of a circle and ∠ABC = 135°, then the ratio of arc \[\stackrel\frown{ABC}\] to the circumference is ______.
In the following figure, AB and CD are two chords of a circle intersecting each other at point E. Prove that ∠AEC = `1/2` (Angle subtended by arc CXA at centre + angle subtended by arc DYB at the centre).
