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Question
In the given figure, O is the centre of a circle and PQ is a diameter. If ∠ROS = 40°, find ∠RTS.
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Solution
It is given that O is the centre and \[\angle ROS = 40° \]
We have `angle RQS = 1/2 angle ROS = 20°`
In right angled triangle RQT we have
\[\angle RQT + \angle QTR + \angle TRQ = 180° \]
\[ \Rightarrow 20° + \angle QTR + 90° = 180° \]
\[ \Rightarrow \angle QTR = 70° \]
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