English

If y = cosx+cosx+cosx+......∞, show that dydx=sinx1-2y - Mathematics and Statistics

Advertisements
Advertisements

Question

If y = `sqrt(cos x + sqrt(cos x + sqrt(cos x + ...... ∞)`, show that `("d"y)/("d"x) = (sin x)/(1 - 2y)`

Sum
Advertisements

Solution

y = `sqrt(cos x + sqrt(cos x + sqrt(cos x + ...  ∞)`

∴ y2 = `cos x + sqrt(cos x + sqrt(cos x + ...  ∞)`

∴ y2 = cos x + y

Differentiating w. r. t. x, we get

`2y ("d"y)/("d"x) = -sin x + ("d"y)/("d"x)`

∴ `("d"y)/("d"x)(1 - 2y)` = sin x

∴ `("d"y)/("d"x) = (sin x)/(1 - 2y)`

shaalaa.com
Differentiation
  Is there an error in this question or solution?
Chapter 2.1: Differentiation - Short Answers II

RELATED QUESTIONS

Differentiate the following w.r.t. x:

(x3 – 2x – 1)5


Differentiate the following w.r.t.x:

`sqrt(x^2 + sqrt(x^2 + 1)`


Differentiate the following w.r.t.x: cos(x2 + a2)


Differentiate the following w.r.t.x: `e^(3sin^2x - 2cos^2x)`


Differentiate the following w.r.t.x: cos2[log(x2 + 7)]


Differentiate the following w.r.t.x:

tan[cos(sinx)]


Differentiate the following w.r.t.x: sec[tan (x4 + 4)]


Differentiate the following w.r.t.x: `sinsqrt(sinsqrt(x)`


Differentiate the following w.r.t.x:

`(x^3 - 5)^5/(x^3 + 3)^3`


Differentiate the following w.r.t.x:

log (sec 3x+ tan 3x)


Differentiate the following w.r.t.x: `(1 + sinx°)/(1 - sinx°)`


Differentiate the following w.r.t. x:

`(x^2 + 2)^4/(sqrt(x^2 + 5)`


Differentiate the following w.r.t. x : cosec–1 (e–x)


Differentiate the following w.r.t. x :

cos3[cos–1(x3)]


Differentiate the following w.r.t. x : `sin^4[sin^-1(sqrt(x))]`


Differentiate the following w.r.t. x : `cot^-1[cot(e^(x^2))]`


Differentiate the following w.r.t. x : `cos^-1(sqrt((1 + cosx)/2))`


Differentiate the following w.r.t. x : `tan^-1((cos7x)/(1 + sin7x))`


Differentiate the following w.r.t. x : `tan^-1(sqrt((1 + cosx)/(1 - cosx)))`


Differentiate the following w.r.t. x : `sin^-1((cossqrt(x) + sinsqrt(x))/sqrt(2))`


Differentiate the following w.r.t. x : `cos^-1((3cos3x - 4sin3x)/5)`


Differentiate the following w.r.t. x : `sin^-1((1 - x^2)/(1 + x^2))`


Differentiate the following w.r.t. x : `cot^-1((1 - sqrt(x))/(1 + sqrt(x)))`


Differentiate the following w.r.t. x : `tan^-1((2sqrt(x))/(1 + 3x))`


Differentiate the following w.r.t. x :

`tan^-1((5 -x)/(6x^2 - 5x - 3))`


Differentiate the following w.r.t. x : `cot^-1((4 - x - 2x^2)/(3x + 2))`


Differentiate the following w.r.t. x :

`(x +  1)^2/((x + 2)^3(x + 3)^4`


Differentiate the following w.r.t. x : `root(3)((4x - 1)/((2x + 3)(5 - 2x)^2)`


Differentiate the following w.r.t. x : `(x^2 + 3)^(3/2).sin^3 2x.2^(x^2)`


Differentiate the following w.r.t. x : `((x^2 + 2x + 2)^(3/2))/((sqrt(x) + 3)^3(cosx)^x`


Differentiate the following w.r.t. x : (sin x)x 


Differentiate the following w.r.t. x :

(sin x)tanx + (cos x)cotx 


Differentiate the following w.r.t. x : `10^(x^(x)) + x^(x(10)) + x^(10x)`


Show that `"dy"/"dx" = y/x` in the following, where a and p are constants: `log((x^20 - y^20)/(x^20 + y^20))` = 20


Solve the following : 

The values of f(x), g(x), f'(x) and g'(x) are given in the following table :

x f(x) g(x) f'(x) fg'(x)
– 1 3 2 – 3 4
2 2 – 1 – 5 – 4

Match the following :

A Group – Function B Group – Derivative
(A)`"d"/"dx"[f(g(x))]"at" x = -1` 1.  – 16
(B)`"d"/"dx"[g(f(x) - 1)]"at" x = -1` 2.     20
(C)`"d"/"dx"[f(f(x) - 3)]"at" x = 2` 3.  – 20
(D)`"d"/"dx"[g(g(x))]"at"x = 2` 5.     12

If y = sin−1 (2x), find `("d"y)/(""d"x)` 


If y = `"e"^(1 + logx)` then find `("d"y)/("d"x)` 


If y = `sin^-1[("a"cosx - "b"sinx)/sqrt("a"^2 + "b"^2)]`, then find `("d"y)/("d"x)`


y = {x(x - 3)}2 increases for all values of x lying in the interval.


If y = `(3x^2 - 4x + 7.5)^4, "then"  dy/dx` is ______ 


If x = p sin θ, y = q cos θ, then `dy/dx` = ______ 


Find `(dy)/(dx)`, if x3 + x2y + xy2 + y3 = 81


Let f(x) be a polynomial function of the second degree. If f(1) = f(–1) and a1, a2, a3 are in AP, then f’(a1), f’(a2), f’(a3) are in ______.


If y = log (sec x + tan x), find `dy/dx`.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×