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Differentiate tan-1(8x1-15x2) w.r. to x

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Question

Differentiate `tan^-1((8x)/(1 - 15x^2))` w.r. to x

Sum
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Solution

Let y = `tan^-1((8x)/(1 - 15x^2))` 

= `tan^-1((5x + 3x)/(1 - (5x)(3x)))`

= tan−1 5x + tan−1 3x

Differentiating w. r. t. x, we get

`("d"y)/("d"x) = "d"/("d"x)(tan^-1 5x + tan^-1 3x)`

= `1/(1 + (5x)^2)*"d"/("d"x)(5x) + 1/(1 + (3x)^2)*"d"/("d"x)(3x)`

= `1/(1 + 25x^2)*(5) + 1/(1 + 9x^2)*3`

∴ `("d"y)/("d"x) = 5/(1 + 25x^2) + 3/(1 + 9x^2)`

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Chapter 2.1: Differentiation - Short Answers II

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