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Question
If y = sin−1 (2x), find `("d"y)/(""d"x)`
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Solution
y = sin−1 (2x)
∴ `("d"y)/("d"x) = "d"/("d"x)[sin^-1 (2^x)]`
= `1/sqrt(1 - (2^x)^2) * "d"/("d"x)(2^x)`
= `(2^x log2)/sqrt(1 - (2^x)^2`
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