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If y = sin−1 (2x), find dydx

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Question

If y = sin−1 (2x), find `("d"y)/(""d"x)` 

Sum
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Solution

y = sin−1 (2x

∴ `("d"y)/("d"x) = "d"/("d"x)[sin^-1 (2^x)]`

= `1/sqrt(1 - (2^x)^2) * "d"/("d"x)(2^x)`

= `(2^x log2)/sqrt(1 - (2^x)^2`

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Chapter 2.1: Differentiation - Very Short Answers

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