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Differentiate the following w.r.t.x: [log {log(logx)}]2

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Question

Differentiate the following w.r.t.x: [log {log(logx)}]2

Sum
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Solution

Let y = [log {log(logx)}]2 
Differentiating w.r.t. x, we get
`"dy"/"dx" = "d"/"dx"[log{log(logx)}]^2`

= `2.log{log(logx)} xx "d"/"dx"[log{log(logx)}]`

= `2.log{log(logx)} xx (1)/(log(logx))."d"/"dx"[log(logx)]`

= `2.log{log(logx)} xx (1)/(log(logx)). (1)/(logx) xx "d"/"dx"(logx)`

= `2.log{log(logx)} xx (1)/(log(logx)). (1)/(logx) xx (1)/x`

= `2.[(log{log(logx)})/(x.logx.log(logx))]`.

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Chapter 1: Differentiation - Exercise 1.1 [Page 12]

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