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Differentiate the following w.r.t.x: loge2(logx)

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Question

Differentiate the following w.r.t.x: `log_(e^2) (log x)`

Sum
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Solution

Let y = `log_(e^2) (log x)`

∴ y = `log (log x)/(log e^2)                   ...[∴ log_b a = (log a)/(log b)]`

∴ y = `log (log x)/(2 log e)                   ...[∴ log x^a = alog x]`

∴ y = `log (log x)/(2)                            ...[∴  log e = 1]`

Differentiating w.r.t.x, we get,

`"dy"/"dx" = 1/2 "d"/"dx" log (log x)`

`"dy"/"dx" = 1/2 × 1/(log x). "d"/"dx" (log x)`

`"dy"/"dx" = 1/2 × 1/(log x). 1/x`

`"dy"/"dx" = 1/(2x(log x))`

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Chapter 1: Differentiation - Exercise 1.1 [Page 12]

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