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Differentiate the following w.r.t. x : tan-1[1-tan(x2)1+tan(x2)]

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Question

Differentiate the following w.r.t. x : `tan^-1[(1 - tan(x/2))/(1 + tan(x/2))]`

Sum
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Solution

Let y = `tan^-1[(1 - tan(x/2))/(1 + tan(x/2))]`

= `tan^-1[(tan(pi/4) - tan(x/2))/(1 + tan(pi/4).tan(x/2))]      ...[∵ tan  pi/4 = 1]`

= `tan^-1[tan(pi/4 - x/2)]`

= `pi/(4) - x/(2)`
Differentiating w.r.t. x, we get
`"dy"/"dx" = "d"/"dx"(pi/4 - x/2)`

= `"d"/"dx"(pi/4) - (1)/(2)"d"/"dx"(x)`

= `0 - (1)/(2) xx 1`

= `-(1)/(2)`.

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Chapter 1: Differentiation - Exercise 1.2 [Page 29]

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