English

Differentiate the following w.r.t. x : cos-1(1-cos(x2)2)

Advertisements
Advertisements

Question

Differentiate the following w.r.t. x :

`cos^-1(sqrt(1 - cos(x^2))/2)`

Sum
Advertisements

Solution

Let y = `cos^-1(sqrt(1 - cos(x^2))/2)`

= `cos^-1(sqrt((2sin^2(x^2/2))/2))`

= `cos^-1[sin(x^2/2)]`

= `cos^-1[cos(pi/2 - x^2/2)]`

= `pi/(2) - x^2/(2)`
Differentiating w.r.t. x, we get
`"dy"/"dx" = "d"/"dx"(pi/2 - x^2/2)`

= `"d"/"dx"(pi/2) - (1)/(2)"d"/"dx"(x^2)`

= `0 - (1)/(2) xx 2x`
= – x.

shaalaa.com
  Is there an error in this question or solution?
Chapter 1: Differentiation - Exercise 1.2 [Page 29]

RELATED QUESTIONS

Differentiate the following w.r.t. x:

(x3 – 2x – 1)5


Differentiate the following w.r.t. x: `sqrt(x^2 + 4x - 7)`.


Differentiate the following w.r.t.x: `sqrt(tansqrt(x)`


Differentiate the following w.r.t.x: log[cos(x3 – 5)]


Differentiate the following w.r.t.x: `e^(3sin^2x - 2cos^2x)`


Differentiate the following w.r.t.x: cos2[log(x2 + 7)]


Differentiate the following w.r.t.x: `log[sec (e^(x^2))]`


Differentiate the following w.r.t.x: `log_(e^2) (log x)`


Differentiate the following w.r.t.x:

sin2x2 – cos2x2 


Differentiate the following w.r.t.x:

(x2 + 4x + 1)3 + (x3− 5x − 2)4 


Differentiate the following w.r.t.x: (1 + 4x)5 (3 + x −x2)8 


Differentiate the following w.r.t.x:

`(x^3 - 5)^5/(x^3 + 3)^3`


Differentiate the following w.r.t.x:

log (sec 3x+ tan 3x)


Differentiate the following w.r.t.x: `(e^sqrt(x) + 1)/(e^sqrt(x) - 1)`


Differentiate the following w.r.t.x: log[tan3x.sin4x.(x2 + 7)7]


Differentiate the following w.r.t.x:

`log(sqrt((1 + cos((5x)/2))/(1 - cos((5x)/2))))`


Differentiate the following w.r.t. x : cosec–1 (e–x)


Differentiate the following w.r.t. x: 

`sin^-1(sqrt((1 + x^2)/2))`


Differentiate the following w. r. t. x.

cos–1(1 – x2)


Differentiate the following w.r.t. x : `sin^-1(x^(3/2))`


Differentiate the following w.r.t. x : `"cosec"^-1[1/cos(5^x)]`


Differentiate the following w.r.t. x : `tan^-1[(1 + cos(x/3))/(sin(x/3))]`


Differentiate the following w.r.t. x : `cot^-1((sin3x)/(1 + cos3x))`


Differentiate the following w.r.t. x :

`cot^-1[(sqrt(1 + sin  ((4x)/3)) + sqrt(1 - sin  ((4x)/3)))/(sqrt(1 + sin  ((4x)/3)) - sqrt(1 - sin  ((4x)/3)))]`


Differentiate the following w.r.t. x :

`cos^-1  ((1 - 9^x))/((1 + 9^x)`


Differentiate the following w.r.t. x :

`sin^-1(4^(x + 1/2)/(1 + 2^(4x)))`


Differentiate the following w.r.t. x : `cot^-1((1 - sqrt(x))/(1 + sqrt(x)))`


Differentiate the following w.r.t. x : `tan^-1((a + btanx)/(b - atanx))`


Differentiate the following w.r.t. x : `root(3)((4x - 1)/((2x + 3)(5 - 2x)^2)`


Differentiate the following w.r.t. x: `x^(tan^(-1)x`


Differentiate the following w.r.t. x : (sin x)x 


Differentiate the following w.r.t. x: (sin xx)


Differentiate the following w.r.t. x: xe + xx + ex + ee.


Show that `"dy"/"dx" = y/x` in the following, where a and p are constants : x7.y5 = (x + y)12 


Show that `bb("dy"/"dx" = y/x)` in the following, where a and p are constant:

xpy4 = (x + y)p+4, p ∈ N


Show that `"dy"/"dx" = y/x` in the following, where a and p are constants : `sec((x^5 + y^5)/(x^5 - y^5))` = a2 


Show that `"dy"/"dx" = y/x` in the following, where a and p are constants : `tan^-1((3x^2 - 4y^2)/(3x^2 + 4y^2))` = a2 


If y is a function of x and log (x + y) = 2xy, then the value of y'(0) = ______.


Differentiate y = etanx w.r. to x


Differentiate `sin^-1((2cosx + 3sinx)/sqrt(13))` w.r. to x


If y = `sqrt(cos x + sqrt(cos x + sqrt(cos x + ...... ∞)`, show that `("d"y)/("d"x) = (sin x)/(1 - 2y)`


If y = cosec x0, then `"dy"/"dx"` = ______.


Solve `x + y (dy)/(dx) = sec(x^2 + y^2)`


If x = eθ, (sin θ – cos θ), y = eθ (sin θ + cos θ) then `dy/dx` at θ = `π/4` is ______.


Let f(x) be a polynomial function of the second degree. If f(1) = f(–1) and a1, a2, a3 are in AP, then f’(a1), f’(a2), f’(a3) are in ______.


Differentiate `tan^-1 (sqrt((3 - x)/(3 + x)))` w.r.t. x.


Diffierentiate: `tan^-1((a + b cos x)/(b - a cos x))` w.r.t.x.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×