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Question
Differentiate the following w.r.t.x:
tan[cos(sinx)]
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Solution
Let y = tan[cos(sinx)]
Differentiating w.r.t. x, we get
`(dy)/(dx) = d/(dx){tan[cos(sinx)]}`
= `sec^2[cos(sinx)].d/(dx)[cos(sinx)]`
= `sec^2[cos(sinx)].[-sin(sinx)].d/(dx)(sinx)`
= –sec2[cos (sinx)]·sin(sinx)·cosx.
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