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Differentiate the following w.r.t. x : tan-1(2x1+22x+1) - Mathematics and Statistics

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Question

Differentiate the following w.r.t. x : `tan^-1((2^x)/(1 + 2^(2x + 1)))`

Sum
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Solution

Let y = `tan^-1((2^x)/(1 + 2^(2x + 1)))`

= `tan^-1[(2.2^x - 2^x)/(1 + (2.2^x)(2^x))]`
= tan–1(2.2x) – tan–1(2x)
Differentiating w.r.t. x, we get
`"dy"/"dx" = "d"/"dx"[tan^-1(2.2^x) - tan^-1(2^x)]`

= `"d"/"dx"[tan^-1(2.2^x)] - "d"/"dx"[tan^-1(2^x)]`

= `(1)/(1 + (2.2^x)^2)."d"/"dx"(2.2^x) - (1)/(1 + (2^x)^2)."d"/"dx"(2^x)`

= `(1)/(1 + 4(2^(2x))) xx 2 xx 2^xlog2 - (1)/(1 + 2^(2x)) xx 2^xlog2`

= `2^xlog2[2/(1 + 4(2^(2x))) - 1/(1 + 2^(2x))]`.

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Chapter 1: Differentiation - Exercise 1.2 [Page 30]

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