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Question
Differentiate the following w.r.t. x : cot–1(x3)
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Solution
Let y = cot–1(x3)
Differentiating w.r.t. x, we get
`"dy"/"dx" = "d"/"dx"[cot^-1(x^3)]`
= `(-1)/(1 + (x^3)^2)."d"/"dx"(x^3)`
= `(-1)/(1 + x^6) xx 3x^2`
= `(-3x^2)/(1 + x^6)`.
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