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If the equation of the base of an equilateral triangle is x + y = 2 and the vertex is (2, – 1), then find the length of the side of the triangle.

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Question

If the equation of the base of an equilateral triangle is x + y = 2 and the vertex is (2, – 1), then find the length of the side of the triangle.

Sum
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Solution

Equation of the base AB of a ΔABC is x + y = 2

In ΔABD,

sin 60° = `"AD"/"AB"`

⇒ `sqrt(3)/2 = "AD"/"AB"`

⇒ AD = `sqrt(3)/2 "AB"`


Length of perpendicular from A(2, – 1) to the line x + y = 2 is
AD = `|(1 xx 2 + 1 xx -1 - 2)/sqrt((1)^2 + (1)^2)|`

⇒ `sqrt(3)/2 "AB" = |(2 - 1 - 2)/sqrt(2)| = |(-1)/sqrt(2)|`

⇒ `sqrt(3)/2 "AB" = 1/sqrt(2)`

⇒ AB = `sqrt(2)/sqrt(2)`

Hence, the required length of side = `sqrt(2/3)`.

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Chapter 10: Straight Lines - Exercise [Page 179]

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NCERT Exemplar Mathematics [English] Class 11
Chapter 10 Straight Lines
Exercise | Q 13 | Page 179

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